When are the natural embeddings of classical invariant rings pure?

Authors

Melvin Hochster, University of Michigan
Jack Jeffries, University of Nebraska-LincolnFollow
Vaibhav Pandey, Purdue University
Anurag K. Singh, University of Utah

Document Type

Article

Date of this Version

7-5-2023

Citation

Forum of Mathematics, Sigma (2023), Vol. 11:e67 1–43 doi:10.1017/fms.2023.67

Comments

Open access.

Abstract

Consider a reductive linear algebraic group G acting linearly on a polynomial ring S over an infinite field; key examples are the general linear group, the symplectic group, the orthogonal group, and the special linear group, with the classical representations as inWeyl’s book: For the general linear group, consider a direct sum of copies of the standard representation and copies of the dual; in the other cases, take copies of the standard representation. The invariant rings in the respective cases are determinantal rings, rings defined by Pfaffians of alternating matrices, symmetric determinantal rings and the Plücker coordinate rings of Grassmannians; these are the classical invariant rings of the title, with 𝑆^𝐺 ⊆ 𝑆 being the natural embedding.

Over a field of characteristic zero, a reductive group is linearly reductive, and it follows that the invariant ring 𝑆^𝐺 is a pure subring of S, equivalently, 𝑆^𝐺 is a direct summand of S as an 𝑆^𝐺-module. Over fields of positive characteristic, reductive groups are typically no longer linearly reductive. We determine, in the positive characteristic case, precisely when the inclusion 𝑆^𝐺 ⊆ 𝑆 is pure. It turns out that if 𝑆^𝐺 ⊆ 𝑆 is pure, then either the invariant ring 𝑆^𝐺 is regular or the group G is linearly reductive.